:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
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:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1(1/T+1/
:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
(2/T+6)*4+{1/T+6T-24)}=1
8/T+24+1/T+6T-24=1
9/T+6T=1
9+6T²=T(T>0)
6T²-T+9=0
判别式=(-1)²-4×6×9<0,因此在实数范围内无解
:解(1/T+1/T+6)*4+{1/T+6*(T-4)}=1
5t-3≤4t-1 7+2t>6+3t 3+t
5t-3≤4t-1 7+2t>6+3t 3+t
4t^-8t+5-3t^+6t-2 其中t=2/1
(2t+3)(2t-)-(4t+1)(t-9)
(t^5+t^4+t^3+t^2+t+1)(t-1) 用直式计算
t-1/3t-1/4t-1/5t=13怎样解
3t/4t-6,t+1/4t^2-9
[T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.')
已知t >0,则函数y =(t*t-4t+1)/t的最小值
t/(t^2-t+1)的积分
利用行列式的性质证明| 1 1 1 || t t^2 t^3 |=t^4(t-1)^3(t+1) [这里的数字都是次方)| t^2 t^4 t^6 |
t-1
求解数学题∫(3t+1)/(t*t-t+1)
计算 (t+2)(t²-t+1)+t-2
3t平方-1=6t
3t^2-1=6t
(t+1)^2(t-1)^2(t^2+t+1)^2(t^2-t+1)^2的答案是否为t^12-2t^6+1