计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/05 18:50:51
计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(

计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)
计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)

计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)
[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)
=[(y+1)/(y-1)(y-3)减去(y-2)/(y-3)^2]除以(y-5)/(y-1)
=[(y+1)(y-3)/(y-1)(y-3)^2减去(y-2)(y-1)/(y-1)(y-3)^2]除以(y-5)/(y-1)
=(y-5)/(y-1)(y-3)^2除以(y-5)/(y-1)
=(y-5)/(y-1)(y-3)^2乘以(y-1)/(y-5)
=1/(y-3)^2