锛坸+y)虏-16(x-y)虏
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/18 07:45:08
锛坸+y)虏-16(x-y)虏锛坸+y)虏-16(x-y)虏锛坸+y)虏-16(x-y)虏(x+y)²-16(x-y)²=[(x+y)+4(x-y)][(x+y)-4(x-y)]=
锛坸+y)虏-16(x-y)虏
锛坸+y)虏-16(x-y)虏
锛坸+y)虏-16(x-y)虏
(x+y)²-16(x-y)²
=[(x+y)+4(x-y)][(x+y)-4(x-y)]
=(x+y+4x-4y)(x+y-4x+4y)
=(5x-3y)(5y-3x)
明白请采纳,有疑问请追问!
有新问题请求助,谢谢!
锛坸+y)虏-16(x-y)虏
(y-x)虏-(x+y)(x-y)锲犲纺鍒呜В
[(3x+y)虏-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy) 是[(3x+y)²-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
宸茬煡{(x-2)虏-(x+y)虏+y(2x-y)}梅(-2y)=2,姹
宸茬煡X虏-Y虏=8,X-Y=2,姹俋虏+Y虏镄勫
(x+y)^2-16(x-y)^2
16-8(x-y)+(x-y)平方
(x+y)²-16(x-y)²
(x+y)^2-16(x-y)^2
16-8（x-y)+(x-y)2
{(x,y) |x|+|y|
x>y?x:y
宸茬煡x虏+y虏+2x-6y+10=0,姹倄^ yx²+y²+2x-6y+10=0,求x^ y
(x-6y)(x+2y)+16y^2 因式分解
(x+2y)虏-(x-2y)(x+2y)+(x-2y)(2y+x),最好能够运用平方差公式或完全平方公式(x+2y)^2-(x-2y)(x+2y)+(x-2y)(2y+x)，最好能够运用平方差公式或完全平方公式
（16x^4+y^4)(4x^2+y^2)(2x-y)(2x+y)
(16x^4+y^4)(4x^2+y^2)(2x-y)(2x+y)
把16y-x^2y因式分解