y={ 2x+3 x
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y={2x+3xy={2x+3x1}的最大值为y={2x+3x分段讨论.x≤0时,y=2x+3,单调递增,x=0时,有ymax=30x>1时,y=-x+5,单调递减,y综上,得y最大值为4.
y={ 2x+3 x
y={ 2x+3 x<=0 x+3 0
y={ 2x+3 x
分段讨论.
x≤0时,y=2x+3,单调递增,x=0时,有ymax=3
0
综上,得y最大值为4.
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x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20