圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.
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圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.圆(x+3)^2+(y--5)^2=16的圆心到原点
圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.
圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.
圆(x+3)^2+(y--5)^2=16的圆心到原点的距离为______.
d=√ (3-0)平方+（-5-0）平方=√（9+25）=√34
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