忘了我?
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忘了我?忘了我? 忘了我?1+1/n=(n+1)/n∴an=an-1+ln[n/(n-1)=an-2+ln[(n-1)/(n-2)]+ln[n/(n-1)]=an-2+ln[n/(n-1)*
忘了我?
忘了我?
忘了我?
1+1/n=(n+1)/n
∴an=an-1+ln[n/(n-1)
=an-2+ln[(n-1)/(n-2)]+ln[n/(n-1)]
=an-2+ln[n/(n-1)*(n-1)/(n-2)]
=.
=a1+ln[n/(n-1)*(n-1)/(n-2)*...*2/1]
=a1+lnn
=2+lnn