已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=

来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/13 18:52:24
已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4

已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=
已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=

已知x∈(-π/2,0),cosx=4/5,则tan(x-π/4)=
已知x∈(-π/2,0),cosx=4/5
所以sinx=-√[1-(4/5)²]=-3/5
所以tanx=sinx/cosx=(-3/5)/(4/5)=-3/4
所以tan(x-π/4)=[tanx-tan(π/4)]/[1+tanx*tan(π/4)]=(-3/4-1)/[1+(-3/4)*1]=-7