(3x+2y-5z+1)(-3x+2y-5z-1)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 06:44:09
(3x+2y-5z+1)(-3x+2y-5z-1)(3x+2y-5z+1)(-3x+2y-5z-1)(3x+2y-5z+1)(-3x+2y-5z-1)原式=[(2y-5z)+(3x+1)][(2y-5
(3x+2y-5z+1)(-3x+2y-5z-1)
(3x+2y-5z+1)(-3x+2y-5z-1)
(3x+2y-5z+1)(-3x+2y-5z-1)
原式=[(2y-5z)+(3x+1)][(2y-5z)-(3x+1)]
=(2y-5z)²+(3x+1)²
=4y²-20yz+25z²-9x²-6x-1
1、
原式=a²+2a[a(a+1)]+(a²+a)²
=a²+2a(a²+a)+(a²+a)²
=[a+(a²+a)]²
=(a²+2a)²
=a²(a+2)²
2、
原式=(x²+4)²-(4x)²
=(x²+4x+4)(x²-4x+4)
=(x+2)²(x-2)²
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算
x/2=y/3=z/5 x+3y-z/x-3y+z
已知3x=4Y,5Y=6Z,求 (1)x:y:z;(2)x+y/y+z.请说明道理,
(3x+2y-5z+1)(-3x+2y-5z-1)
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
已知xyz≥0,x+y+z=1,化简x(2y-z)/(1+x+3y)+y(2z-x) /(1+y+3z) +z(2x-y)/(1+z+3x)
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
因式分解:25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y)
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
(2x-3y+z)-3{x-2【-z+(x-y)】-(3y-5z)}
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
2x-y+3z=3 {3X+Y-2Z=-1 X+Y+Z=5