若x-3y+2=0,则11-3x+9y的值为多少
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若x-3y+2=0,则11-3x+9y的值为多少若x-3y+2=0,则11-3x+9y的值为多少若x-3y+2=0,则11-3x+9y的值为多少11-3x+9y=11-3(x-3y+2)+6=11-0
若x-3y+2=0,则11-3x+9y的值为多少
若x-3y+2=0,则11-3x+9y的值为多少
若x-3y+2=0,则11-3x+9y的值为多少
11-3x+9y = 11 -3(x-3y+2) + 6 = 11 - 0 + 6 = 17
由x-3y+2=0可知x-3y=-2 则3x-9y=-6
那么11-3x+9y=11-(3x-9y)=11-(-6)=17
有x-3y=-2;所以11-3x+9y=11-3*(x-3y)=11-3*(-2)=17
解: 由于x-3y+2=0........>x-3y=-2
则11-3x+9y=11-3(x-3y).......>11-3*(12)=11+6=17
所以:11-3x+9y=17
17
x-3y+2=0 则-x+3y=2 而11-3x+9y=11+3(-x+3y)=11+3*2=11+6=17
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