5x+3y=36 3x+y=20
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5x+3y=363x+y=205x+3y=363x+y=205x+3y=363x+y=20答案:x=6,y=2解决方法:5x+3y=36①3x+y=20②将算式②*3,变成9x+3y=60③变成算式③
5x+3y=36 3x+y=20
5x+3y=36 3x+y=20
5x+3y=36 3x+y=20
答案:x=6,y=2
解决方法:
5x+3y=36 ①
3x+y=20 ②
将算式②*3,变成9x+3y=60 ③ 变成算式③
然后将算式③-算式①,左右想对应减去,变成4x=24④,
由算式④可得出x=6,
再将x=6代入算式②,由此可算出y=2
先标一式和二式 2式×3 相减
5x+3y=36······a
3x+y=20·····b
3b得
9x+3y=60·····c
c-a得
4x=24
x=6
y=2
5x+3y=36 ①
3x+y=20 ②
②×3-①,得
4x=24,
∴x=6
代入②式得,y=2
∴x=6,y=2
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