sin²α+sin(90-α)=?-0-

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sin²α+sin(90-α)=?-0-sin²α+sin(90-α)=?-0-sin²α+sin(90-α)=?-0-sin²α+sin²(90-α

sin²α+sin(90-α)=?-0-
sin²α+sin(90-α)=?
-0-

sin²α+sin(90-α)=?-0-
sin²α+sin²(90-α)= 后面加了一个平方
=sin²a+cos²a
=1