若|3x-2y|+|5+3y|=0,则x²-2y=若|x-1|+|2y-5|+|4+3z|=0,则x²-y²+xyz=
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若|3x-2y|+|5+3y|=0,则x²-2y=若|x-1|+|2y-5|+|4+3z|=0,则x²-y²+xyz=若|3x-2y|+|5+3y|=0,则x²
若|3x-2y|+|5+3y|=0,则x²-2y=若|x-1|+|2y-5|+|4+3z|=0,则x²-y²+xyz=
若|3x-2y|+|5+3y|=0,则x²-2y=
若|x-1|+|2y-5|+|4+3z|=0,则x²-y²+xyz=
若|3x-2y|+|5+3y|=0,则x²-2y=若|x-1|+|2y-5|+|4+3z|=0,则x²-y²+xyz=
|3x-2y|+|5+3y|=0
所以3x-2y=0,5+3y=0
则y=-5/3
x=2y/3=-10/9
所以x²-2y=100/81+10/3=370/81
|x-1|+|2y-5|+|4+3z|=0
所以x-1=2y-5=4+3z=0
所以x=1,y=5/2,z=-4/3
所以x²-y²+xyz=1-25/4-10/3=-103/12
要使结果为0,每个绝对值里的数必须为0,所以x=1 y=5/2 z=-4/3 结果为-113/12
第一问:由5+3y=0得y=-5/3,3x-2y=0得x=-10/9。则x^2-2y=370/81
第二问:由4+3z=0得z=-4/3,x-1=0得x=1,2y-5=0得y=5/2。则x^2-y^2+xyz=-103/12
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