若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=
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若x,y满足|2x-y-3|+|3x+2y+1|=0,则x=y=若x,y满足|2x-y-3|+|3x+2y+1|=0,则x=y=若x,y满足|2x-y-3|+|3x+2y+1|=0,则x=y=2x-y
若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=
若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=
若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y=
2x-y-3=3x+2y+1=0,x=5/7,y=-11/7
绝对值相加等于零当然是两个绝对值都等于零啦,然后联立两个式子,把x,y解出来
根据原式可得、
2x-y-3=0和3x+2y+1=0
将两式联立、解二元一次方程、
得x=5/7、y=-11/7
x=5/7 y=-11/7
x= 7分之5 y=负7分之11
2x-y=3
3x+2y=-1
6x-3y=9
6x+4y=-2
-7y=11
y=-11/7
2x=3-11/7
=10/7
x=5/7
y=-11/7 x=5/7
因为两个绝对值的和等于零,而绝对值为非负数,要等于零,所以绝对值里的数都为零.即2x-y-3=0和3x+2y+1=0解这个方程组就得到x=5/7,y=-21/7.
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