(2x-y-3)^2+│10-3x-4y│=0,x=( ),y=( )

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(2x-y-3)^2+│10-3x-4y│=0,x=(),y=()(2x-y-3)^2+│10-3x-4y│=0,x=(),y=()(2x-y-3)^2+│10-3x-4y│=0,x=(),y=()(

(2x-y-3)^2+│10-3x-4y│=0,x=( ),y=( )
(2x-y-3)^2+│10-3x-4y│=0,x=( ),y=( )

(2x-y-3)^2+│10-3x-4y│=0,x=( ),y=( )
(2x-y-3)^2+│10-3x-4y│=0
2x-y-3=0,--->y=2x-3
10-3x-4y=0
10-3x-4(2x-3)=0
10-3x-8x+12=0
x=2
y=2*2-3=1

2x-y-3=0 和 10-3x-4y=0
得到x=2，y=1

(2x-y-3)^2+│10-3x-4y│=0
因为(2x-y-3)²>=0,|10-3x-4y|>=0
所以只能有
2x-y-3=0
10-3x-4y=0
由第一个方程得y=2x-3,代入第二个方程得
10-3x-4(2x-3)=0
10-3x-8x+12=0
22=11x,x=2,代回去求得y=2x-3=1

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