若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?
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若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?X
若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?
若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?
若|x+3-y|+(x+y-7)^2=0,则(2x-y)^2的值?
X=2,Y=5,所以最终答案为1,因为非负数之和为零,则每一项都为零,所以X+3-Y=0,X+Y-7=0然后解这个方程组就可以了
两个非负数的和就0,这两个数都为0,所以 x+3-y=0 x+y-7=0 解方程组得 x=2,y=5 (2x-y)^2 = 1
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