计算[x²-x-2/x²-x-6]/[x²+x-6/x²+x-2]的结果是.

计算[x²-x-2/x²-x-6]/[x²+x-6/x²+x-2]的结果是.
计算[x²-x-2/x²-x-6]/[x²+x-6/x²+x-2]的结果是.

计算[x²-x-2/x²-x-6]/[x²+x-6/x²+x-2]的结果是.
原式=[(x²-x-2)/(x²-x-6)]÷[(x²+x-6)/(x²+x-2)]
=[(x-2)(x+1)]/[(x-3)(x+2)] ÷[(x-2)(x+3)]/[(x-1)(x+2)]
=[(x-2)(x+1)]/[(x-3)(x+2)] ×[(x-1)(x+2)]/[(x-2)(x+3)]
=[(x+1)(x-1)]/[(x+3)(x-3)]

化简原式=[(x-2)(x+1)/(x-3)(x+2)].[(x+2)(x-1)/(x+3)(x-2)]=(x+1)(x-1)/(x+3)(x-3)=(x²-1)/(x²-9)

[(x-1)(x+1)]/[(x-3)(x+3)]