若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于

若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于

若x²-x-2=0,则x²-2+2√3除以(x²-x)²-1+√3的值等于
x²-x-2=0
x²-x=2
所以原式=(2+2√3)/(2²-1+√3)=(2+2√3)/(3+√3)
=(2+2√3)(3-√3)/(3+√3)(3-√3)
=(6-2√3+6√3-6)/(9-3)
=4√3/6
=2√3/3