f(xy)=f(x)f(y)

f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(

f(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xy游客1:定义在R上的函数f(x)满足f(x+y)=f(x)+f(y)+2xy(x

f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式求什么设

f(xy)=f(x)+f(y)的单调性f(xy)=f(x)+f(y)的单调性f(xy)=f(x)+f(y)的单调性令x=y=0f(0)=f(0)+f(0)f(0)=0令y=-xf(x-x)=f(x)+

f(xy)=f(x)+f(y),证明f(1/x)=-f(x)f(xy)=f(x)+f(y),证明f(1/x)=-f(x)f(xy)=f(x)+f(y),证明f(1/x)=-f(x)证明:取x=1,y=

已知f(xy)=f(x)+f(y),求证f(x/y)=f(x)-f(y)已知f(xy)=f(x)+f(y),求证f(x/y)=f(x)-f(y)已知f(xy)=f(x)+f(y),求证f(x/y)=f

f(x/Y）=f（x）-f(y)求证明f(xy)=f(x)+f(y)f(x/Y）=f（x）-f(y)求证明f(xy)=f(x)+f(y)f(x/Y）=f（x）-f(y)求证明f(xy)=f(x)+f(

以知f(xy)=f(x)+f(y)求证f(x/y)=f(x)－f(y)以知f(xy)=f(x)+f(y)求证f(x/y)=f(x)－f(y)以知f(xy)=f(x)+f(y)求证f(x/y)=f(x)

以知f(x/y)=f(x)－f(y)求证f(xy)=f(x)+f(y)以知f(x/y)=f(x)－f(y)求证f(xy)=f(x)+f(y)以知f(x/y)=f(x)－f(y)求证f(xy)=f(x)

函数f(xy)=f(x)+f(y)如何推出f(x)-f(y)f(xy)=f(x)+f(y)如何推出f(x)-f(y)=f(x/y)还有f(x+y)=f(x)+f(y)如何推出f(x-y)=f(x)-f

f(xy)=f(x)+f(y),f(2)=1,f(3)=?f(xy)=f(x)+f(y),f(2)=1,f(3)=?f(xy)=f(x)+f(y),f(2)=1,f(3)=?f（xy）＝f（x）＋f（

f(xy)=f(x)+f(y)且f(8)=3则f(2)=f(xy)=f(x)+f(y)且f(8)=3则f(2)=f(xy)=f(x)+f(y)且f(8)=3则f(2)=f(4)=f(2)+f(2)=2

f(xy)=f(x)+f(y),f(8)=3,则f(根2)等于f(xy)=f(x)+f(y),f(8)=3,则f(根2)等于f(xy)=f(x)+f(y),f(8)=3,则f(根2)等于f(xy)=f

f(xy)=f(x)+f(y),f(8)=3,求f(√2),f(xy)=f(x)+f(y),f(8)=3,求f(√2),f(xy)=f(x)+f(y),f(8)=3,求f(√2),f(8)=f(2根2

给出下列3个等式f(xy)=f(x)+f(y),f(x+y)=f(x)f(y),f(x+y)=f(x)+f(y),则下列函数中不满足其中任何一个等式的是A：f(x)=3∧xB:f(x)=x∧aC:f(

给出下列三个等式f(x+y)=f(x)+f(y),f(x+y)=f(x).f(y),f(xy)=f(x)+f(y),则下列函数中不满足其中任何一个等式的是（）A.f(x)=2xB.f(x)=2^xC.

给出下列三个等式,f(xy)=f(x)+f(y),f(x+y）=f(x)f(y),f(x+y)=f(x)+f(y),下列函数中不满足其中任何一个等式的是（）A.f(x)=3的x次方B.f(x)=以2为

已知f(x+y)=f(x)+f(y)+2xy,求f(0)已知f(x+y)=f(x)+f(y)+2xy,求f(0)已知f(x+y)=f(x)+f(y)+2xy,求f(0)令x=y=0f(0)=f(0)+

若f(xy)=f(x)+f(y)且f(4)=1求f(1/16)若f（x+y)=f(xy)求f(1）若f(xy)=f(x)+f(y)且f(4)=1求f(1/16)若f（x+y)=f(xy)求f(1）若f

f(x)=y满足f(xy)=f(x)+f(y)求f(1),f(-1)f(x)=y满足f(xy)=f(x)+f(y)求f(1),f(-1)f(x)=y满足f(xy)=f(x)+f(y)求f(1),f(-