f(x+y)=f(x)+f(y)+2xy
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/22 10:06:19
f(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xy游客1:定义在R上的函数f(x)满足f(x+y)=f(x)+f(y)+2xy(x
f(x+y)=f(x)+f(y)+2xy
f(x+y)=f(x)+f(y)+2xy
f(x+y)=f(x)+f(y)+2xy
游客1:定义在R上的函数f(x)满足f(x+y)=f(x)+f(y)+2xy(x,y∈R)f(1)=2,
则f(-3)=?
2:设f(x)是连续偶函数,且当x>0时f(x)是单调函数,则满足f(x)=f(x+3/x+4)的所有x之和为?
3:函数f(x)满足:⑴定义域是(0,+∞)⑵当x>1时,f(x)<2;⑶对任意x,y∈(0,∞)总有f(xy)=f(x)+f(y)-2.求:1,f(1)的值.2,判断函数f(x)的单调性,并用定义予以证明.
4:已知函数f(x)在(-1,1)上有意义,f(1/2)=-1,当且仅当时
f(x+y)=f(x)+f(y)+2xy
f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)
f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式
f(xy,x-y)=x^2+y^2+xy;f(x,y)/∂x;f(x,y)/∂y
已知f(x+y)=f(x)+f(y)+2xy,求f(0)
f(x+y,x-y)=(x^2-y^2)/2xy,求f(x,y)!
f(x+y,x-y)=2xy(x-y),求f(x,y)
f(xy,x-y)=x^2+3xy+y^2,则f(x,y)=?
f(xy,x-y)=x^2-xy+y^2.求f(x,y)
y'=-2xy;求f(x).
f(xy)=f(x)+f(y),f(2)=1,f(3)=?
f(xy)=f(x)+f(y)且f(8)=3则f(2)=
f(xy)=f(x)+f(y),f(8)=3,则f(根2)等于
f(xy)=f(x)+f(y),f(8)=3,求f(√2),
f'(0)=1,f(x+y)=f(x)+f(y)+2xy,求f(x)
f(x)满足f(x+y)+f(xy)=2f(x)f(y)求函数的奇偶性
导数：f(x+y)=f(x)f(y),且f'(o)=1,求f'(x)f(x+y)=f(x)f(y),且f'(o)=1,求f'(x)f(x+y)=f(x)+f(y)+2xy,且f'(o)存在,求f'(x) f(1+x)=af(x),且f'(0)=b,求f'(1)
设f(x+y,x-y)=x^2+xy,求f(x,y)