6x²-141x-48=0

6x²-141x-48=0 已知(x²+y²)(x²+y²-6)+9=0 ,求x²+y²的值. 已知2x²+2x-3=0 求代数式x(x²-x-1)+2(x²+1)-1/3x(3x²+6x) 3x² - 9x + 2 = 0 x² - 14x = 8 x² + 6x = 1 x&sup4-x²-6=0 3x²-x=0,求6x³+7x²-5x+2006 1.若X+X/1=6,求X²+X²/1的值 2.已知X²-6X+1=0,求X²+X²/1的值 3.已知X²+X+ 已知x²+y²+4x-8y+20=0 x=?y=?（x²+y²）²+y²=x²+6 则x²+y= x²+y²-2x-6y+10=0 求分式x²-y²/xy 已知：x²+y²+4x+6y+13=0 求：x²+y²的值 已知:x²-6x+8y+y²+25=0,求x²+2xy+y² x²＋y²—6x+4y+13=0,求x² — y²? 6x²-xy-15y²=0 求x²-2xy+4y²/2x²-3xy-3y²告诉下 6x²-xy-15y²=0 求2x²-3xy-3y²分之x²-2xy+4y² [2(x+1)² / x²]+ [(x+1)/ x] -6=0 若|x+y-5|+(xy-6)²=0,求x²+y²的值. 问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+ (x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =19/6化成(x² +x+1)/(x² +1)+(x² +1)/(x² +x+1)=13/6急嗷