（80%*X-X+50)*10=（50-30)*12 怎样解,

80%X*(1+50%)=10+X 求X是多少? (50-x)*(80+10x)=0, x+ x+(x*50%)=1.5X? x(10-x)=50 x=?x(10-x)=50x=? 10x+2x*[(50-x)/2]+5x[(50-x)/2]=240 130%x+x=4.6 x÷50%=10 x/9-x/15=16% 请把下列算式改为用数学符号,是分式就写成分式,不要用/,^这些320/(x-10)-(320-80+10)/x-80/(x-10)=1320x-250(x-10)-80x=x(x-10)x^2-10x-320x+250x-2500+80x=0x^2-2500=0x1=50,x2=-50(舍去) x+3x+x-2+x+x+50%x=188 求x 50*2X=X*（50-X）*10 2x+8-10x+50=5x-10 =(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+25x^2+10x^2-50x+24 这是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=（x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24 45x+10 =50X（x-1） 5(x/10+x/12)=x-50怎么解 =（x^2-5x+4)(x^2-5x+6) =(x^2-5x)^2+10(x^2-5x)+24 是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=（x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24不好意思我弄错了，是=（x^2-5 50X=200+X*X 30%x=50%x-20x 80%x+30-x=10%x 50%X+20=80%X-40