20×30-(20-x)(32-x)=540怎么解.

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 12:20:03
20×30-(20-x)(32-x)=540怎么解.20×30-(20-x)(32-x)=540怎么解.20×30-(20-x)(32-x)=540怎么解.你是问x等于多少么可以换算成600-X=54

20×30-(20-x)(32-x)=540怎么解.
20×30-(20-x)(32-x)=540怎么解.

20×30-(20-x)(32-x)=540怎么解.
你是问x等于多少么

可以换算成600-X=540,那么(20-X)(32-X)=60

5x+15x =( + )x =20x (x/20)*5+x=30 (16x-13)/(4x-3)-(20x-24)/(4x-5)=(32x-30)/(8x-7)-(40x-43)/(8x-9)求x 麻烦解4道分式方程(20分)(x/2x-5)+(5/5-2x)=1(x+1/x*x-2x)-(1/x)=3/x-2(1-x/5-x)-(5-x/1-x)=8/x*x-6x+5(x+1/x-1)-(4/x*x-1)=1去掉括号,不管前面正负,都不变号~ (30-x):(18+x)=(20+x):(32-x) x+(x+20)+(x-10)+70+x=540 . 8x-3(20-x)=5x (x-20%x)+5=x-3 (x+30)*8=20x 5x-(20-x)=76 5x-(20-x)=64 (16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5).... (16x-13)/(4x-3)+(40x-43)/(8x-9)=(32x-30)/(8x-7)+(20x-24)/(4x-5) 2(x+3)-5(1-x)=3(3-1) 4-3(2-x)=5x 4x-3(20-x)=6x-7(9-x) 4-3(2-x)=5x 4x-3(20-x)=6x-7(9-x)1/3 - x-1/2 = 1x+8/3=-x1-m/2 - 3-3m/4=1x-2/0.2 - x+1/0.5=32(x+3) - 5(1-x) = 3(x-1)4-3(2-x)=5x4x-3(20-x)=6x-7(9-x) 探索:(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1 (x-1)(x^3+x^2+x+1)=x^4-1 (x-1)(x^探索:(x-1)(x+1)=x^2-1 (x-1)(x^2+x+1)=x^3-1 (x-1)(x^3+x^2+x+1)=x^4-1 (x-1)(x^4+x^3+x^2+x+1)=x^5-1试求:2^6+2^5+2^4+2^3+2^2+2+1的值 判断:2^2005+2^2004+2^20 .X²+13X+36 .X²+5X-20 .X²-2X-15 .8(X²+X)²-8(X²+X)+12 请问,这十道关于一元一次方程的题目我做对了吗?(1)2X+3X+4X=189X=18X=2(2)13X-15X+X=-3-1X=-3X=3(3)2.5X+10X-6X=15-21.56.5X=6.5X=1(4)4X+3(2X-3))=12-(X+4)4X+6X-9=12X-4810X-12X=-48+9-2X=-57X=28.5(5) 7X+2(3X-3)=207X+6X-6=2013X=20+6 matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并