(1/3)^[log(1/2)^(x^2-3x+1)]
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(1/3)^[log(1/2)^(x^2-3x+1)](1/3)^[log(1/2)^(x^2-3x+1)](1/3)^[log(1/2)^(x^2-3x+1)]由原式可得(1/3)^[log(1/2
(1/3)^[log(1/2)^(x^2-3x+1)]
(1/3)^[log(1/2)^(x^2-3x+1)]
(1/3)^[log(1/2)^(x^2-3x+1)]
由原式可得(1/3)^[log(1/2)^(x^2-3x+1)]<(1/3)^0
所以log(1/2)^(x^2-3x+1)>0
又因为底数是1/2,所以
0
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