log(1/2)^(x^2+2x-3)>log(2)^[1/(3x-1)]

1/log（2）x+1/log（3）x+1/log（4）x=1,x=? log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, 试解关于x的不等式log(2)x+4log(3)x+12log(8)x+n·2^(n-1)·log(2^n)x log(X+5)+log(X+2)=1 log根号2（X-1) log（x+5）=log（x）+log（2） log（8）+log（x）=log（24） 2log（x）=log(2x)+log(3) log(2)(x)log(2)(4x)-3log(2)(x)-12=0 (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 log(1/2)^(x^2+2x-3)>log(2)^[1/(3x-1)] 2log(x)(25)-3log(25)(x)=1怎么解X啊.急 2log^(x^2) = 3{2^(1+log x)} + 16 2log^(x^2) = 3{2^(1+log x)} + 16 log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y log(2)(x+4)=3^x log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, 2log底3x+log底3 2=1/2log底3 16 x为什么值 log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 2 log(3x)= log 4 +log(6-x)怎么求...急