(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 10:42:38
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2

(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y

(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(4x)=(1/2)x-1-(5/2)y