(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程

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(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程(X+Y分之X+X+Y分之2Y)

(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程
(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程

(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程
原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]
=[xy/(x+y)]×xy/(x+y)
=x²y²/(x+y)²

解原式=x+y分之x+2y乘于x+2y2y分之xy除于(xy分之y+xy分之x)
=x+y分之x+2y乘于x+2y分之xy乘于x+y分之xy
=(x+y)²分之x²y²

看我做的对不对,其实我也是初二的!

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]
=[xy/(x+y)]×xy/(x+y)
=x²y²/(x+y)²