4+x=(24-x)×(1-1/4)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 03:58:33
4+x=(24-x)×(1-1/4)4+x=(24-x)×(1-1/4)4+x=(24-x)×(1-1/4)
4+x=(24-x)×(1-1/4)
4+x=(24-x)×(1-1/4)
4+x=(24-x)×(1-1/4)
解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1
因式分解x^4-11x^2+1还有一道 (x+1)(x+2)(x+3)-24(x+1)(x+2)(x+3)-24没有(x+4)
x²-4x+1=0;x(x-1)=42,求x值,
(x^24 x^23 x^22 …… x)÷(x^8+1)×(x^3+x^2-x-1)÷(x-1)÷(x^4+1)求值(x^24+x^23+x^22+……+x+1)÷(x^8+1)×(x^3+x^2-x-1)÷(x-1)÷(x^4+1)
(x-1)^3(x+1)(x-2)/(x+4)
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
化简[(x+2)/(x²-2x)+(x-1)/(x²-4x+4)]除以(x-4)/x
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
计算:(x+2/x^2-2x-x-1/x^2-4x+4)×x/4-x
(x+2/x^2-2x-x-1/x^2-4x+4)/x-4/x因式分解
3/x-1=4/x 6/x+1=x+5/x(x+1)
计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x
计算.(1+2/x-x+1/x-2)除以x+4/x平方-2x
(2/1-x)-(x/3-x)+(2x-1/x²-4x+3)=1
一元二次方程解答!x(5x+4)=5x+44x^2-45=31x-3x^2+22x-24=0(x+8)(x+1)= -12(3x+2)(x+3)=x+14
解方程:x(2X-3)+2x(x-1)=4x(x-2)+9