若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f'(1)=
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若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f''(1)=若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f''(1)=若f(x)=(x-1)(x-
若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f'(1)=
若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f'(1)=
若f(x)=(x-1)(x-2)...(x-2010)(x-2011),则f'(1)=
设g(x)=(x-2)(x-3)……(x-2011),则:f(x)=(x-1)g(x)
所以:f(x)的导数=g(x)+(x-1)[g(x)的导数]
所以:f(1)的导数=g(1)=(-1)(-2)(-3)……(-2009)(-2010)=2010!
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