(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算
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(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3计算(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3计算(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3计算(
(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算
(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算
(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算
(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3
=0+1/[(-1/2)]+根号27-5-2根号3
=-2+3根号3-5-2根号3
=-7+根号3
两道计算题1、5^-2-(-4)^-2+(π-1)^0 2、(-1/3)^0+(-1/3)^-1+(-1/3)^-2
（1)已知5π/2
(π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算
(π-1)^0+(1/2)^-1+5-根号27的绝对值-2根号3 计算题
(π-1)^0+(1/2)^-1+|5-√27|-2√3=?
sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
cos(2x-π)/[根号2cos(x+π/4)]=-1/5,0
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计算:根号4+(π-2)^0-|-5|+(-1)^2012+(1/3)^-2
|-2|+(π-3)^0-(1/3)^0+(-1)^2010
|-2|+(-1)-(π-√3)0次方
10³+（1/30）^-2×（π-5）^0-（-3）³×0.3^-1+｜-23｜；
求证cosπ/5 + cos3π/5=1/2
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(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009