3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x&su3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x²/4y)²×2y/3x+x²/2y²÷2y²/
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3y/2x+2y+2xy/x²+xy2x/x²-64y²-1/x-8y(1/a+1/b)²÷(1/a²-1/b²)(3x&su3y/2x+2
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x&su3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x²/4y)²×2y/3x+x²/2y²÷2y²/
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x&su
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x²/4y)²×2y/3x+x²/2y²÷2y²/x
计算
3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x&su3y/2x+2y+2xy/x²+xy 2x/x²-64y²-1/x-8y (1/a+1/b)²÷(1/a²-1/b²) (3x²/4y)²×2y/3x+x²/2y²÷2y²/
3y/2x+2y+2xy/x²+xy=3y/2x+2y+2y/x+xy=3y/2x+2y+4y/2x+xy=7y/2x+2y+xy
2x/x²-64y²-1/x-8y =2/x-64y²-1/x-8y =1/x-64y²-8y
(1/a+1/b)²÷(1/a²-1/b²) =(1/a+1/b)²÷[(1/a+1/b)(1/a-1/b)]=(1/a+1/b)÷(1/a-1/b)=(a+b)/(b-a)
最后一题可能题目有点问题,就是+前面的可以化简,约分就可以了.
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