x²+xy-2y²-x+7y-6
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x²+xy-2y²-x+7y-6x²+xy-2y²-x+7y-6x²+xy-2y²-x+7y-6原式=(x+2y)(x-y)-x+7y-6=
x²+xy-2y²-x+7y-6
x²+xy-2y²-x+7y-6
x²+xy-2y²-x+7y-6
原式=(x+2y)(x-y)-x+7y-6
=(x+2y)(x-y)+(2x+4y)-3x+3y-6
=(x+2y)(x-y)+2(x+2y)-3x+3y-6
=(x+2y)(x-y+2)-3(x-y+2)
=(x-y+2)(x+2y-3)
x²-2xy+y²-9
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
因式分解 x²-2xy+y²-z²
计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy
x²-y²+6x+9分之x²+y²-9-2xy
因式分解 x²-XY-2y²-X-Y
x²+xy-2y²-x+7y-6
（xy-x²）÷[（x²-2xy+y²）÷xy]*[(x-y)÷x²]
6x²-xy-15y²=0 求x²-2xy+4y²/2x²-3xy-3y²告诉下
6x²-xy-15y²=0 求2x²-3xy-3y²分之x²-2xy+4y²
谢谢高手解答x²-xy=2,-xy+y²=5求x²-2xy+ y²,x²- y²
因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT
已知：x²+xy=3,xy+y²=-2 求：2x²-xy-3y²
(x+2y)²-x²-2xy
因式分解X²-3Xy+2y²+X-2