x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy

来源：学生作业帮助网编辑：六六作业网时间：2025/02/01 21:09:39

x²-4y²/x²+2xy+y²÷x+2y/2x²+2xyx²-4y²/x²+2xy+y²÷x+2y/2x&s

x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy

x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
(x²-4y²)/(x²+2xy+y²)÷(x+2y)/(2x²+2xy)
=(x-2y)(x+2y)/(x+y)²÷(x+2y)/(2x²+2xy)
=(x-2y)(x+2y)/(x+y)²*(2x²+2xy)/(x+2y)
=(x-2y)/(x+y)²*(2x²+2xy)
=(x-2y)/(x+y)²*2x(x+y)
=(x-2y)/(x+y)*2x
=2x(x-2y)/(x+y)

原式=[(x+2y)(x-2y)/(x+y)²]÷[(x+2y)/2x(x+y)]
=[(x+2y)(x-2y)/(x+y)²][2x(x+y)/(x+2y)]
=2x(x-2y)/(x+y)
=(2x²-4xy)/(x+y)

(x²-4y²)/(x²+2xy+y²) ÷ (x+2y)/(2x²+2xy)
= (x²-4y²)/(x²+2xy+y²) * (2x²+2xy)/(x+2y)
= [(x+2y)(x-2y)]/[(x+y)^2 * [2x(x+y)]/(x+2y)
= (x-2y)/(x+y) * 2x
= 2x(x-2y)/(x+y)

因式分解（x²+y²-1）²-4x²y² 求因式分解：(x²+y²）²-4x²y² (x²+y²)²-4x²y² 因式分解（x²+4y²）²-16x²y² 因式分解分解因式：(x²+y²)²-4x²y² 分解因式：4b²c²-(b²+c²-a²)² 25（x+y)²-16(x-y)² x²-6x+9 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 怎么算啊这个：X²+4X+Y²-2Y+5=0 则X²+Y²=?²²²²²²²²²²²²X²+4X+Y²-2Y+5X=0 则X²+Y²=? -x²/4+y²/9;因式分解 4x²y-xy² 9(x-y)²+12(x²-y²)+4(x+y)² 因式分解已知(x+y)²;=8,(x-y)²;=4,求x²+y² x²+ y ²=4x 求x² + y ²的最大值,最小值若实数x,y满足x²+4y²=4x,求S=x²+y²的取值范围 x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT 计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急化简再求值[(x²+y²）²-4x²y²]÷(x²-y²）其实,x=2,y=2/3.