½ab²·(2a²b-3ab²)(2x-3)²(2x+3)x四次方-1a³(x+y)-ab²(x+y)

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½ab²·(2a²b-3ab²)(2x-3)²(2x+3)x四次方-1a³(x+y)-ab²(x+y)½ab²

½ab²·(2a²b-3ab²)(2x-3)²(2x+3)x四次方-1a³(x+y)-ab²(x+y)
½ab²·(2a²b-3ab²)
(2x-3)²(2x+3)
x四次方-1
a³(x+y)-ab²(x+y)

½ab²·(2a²b-3ab²)(2x-3)²(2x+3)x四次方-1a³(x+y)-ab²(x+y)

我自己做的,希望能采纳,谢谢!

(1)原式=a/b-3/2[这个我是将1/2ab²看作1/(2ab
²)算的]
(2)原式=[(2x)²-3²](2x-3)=(4x²-9)(2x-3)=8x^3-12x²-18x+27
(3)原式=(x^2)^2-1^2=(x^2+1)(x^2-1)=(x^2+1)(x+1)(x-1)
(4)原式=a(x...

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(1)原式=a/b-3/2[这个我是将1/2ab²看作1/(2ab
²)算的]
(2)原式=[(2x)²-3²](2x-3)=(4x²-9)(2x-3)=8x^3-12x²-18x+27
(3)原式=(x^2)^2-1^2=(x^2+1)(x^2-1)=(x^2+1)(x+1)(x-1)
(4)原式=a(x+y)(a²-b²)=a(x+y)(a+b)(a-b)

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x^4-1=(x²)²-1²=(x²+1)(x²-1)=(x²+1)(x+1)(x-1)
a³(x+y)-ab²(x+y)=a(a²-b²)(x+y)=a(a+b)(a-b)(x+y)还有计算呢?(2x-3)²(2x+3)=(2x-3)(2x+3)(2x-3)=(4x²-...

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x^4-1=(x²)²-1²=(x²+1)(x²-1)=(x²+1)(x+1)(x-1)
a³(x+y)-ab²(x+y)=a(a²-b²)(x+y)=a(a+b)(a-b)(x+y)

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