一道英文数学题write an equation for the line that is perpendicular to the given line and that pass thought the given point:y=(-1/3)x+2 ;the point is (4,2)(-10)x+(8)y=3; the point is (15,12)列如:y= 5x +3; the point is (0,2) y =(-1/5)x-2 我
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一道英文数学题write an equation for the line that is perpendicular to the given line and that pass thought the given point:y=(-1/3)x+2 ;the point is (4,2)(-10)x+(8)y=3; the point is (15,12)列如:y= 5x +3; the point is (0,2) y =(-1/5)x-2 我
一道英文数学题
write an equation for the line that is perpendicular to the given line and that pass thought the given point:
y=(-1/3)x+2 ;the point is (4,2)
(-10)x+(8)y=3; the point is (15,12)
列如:
y= 5x +3; the point is (0,2)
y =(-1/5)x-2
我想知道是怎么解的,
一道英文数学题write an equation for the line that is perpendicular to the given line and that pass thought the given point:y=(-1/3)x+2 ;the point is (4,2)(-10)x+(8)y=3; the point is (15,12)列如:y= 5x +3; the point is (0,2) y =(-1/5)x-2 我
y=(-1/3)x+2 ;the point is (4,2)
求一条直线垂直于y=(-1/3)x+2,且过点(4,2)
:所以所求直线为y=kx+b
斜率k=-1/(-1/3)=3
所以y=3x+b,把点(4,2)代入,解b=-10
所以y=3x-10
2、(-10)x+(8)y=3化为y=5x/4+3/8
所以所求直线为y=kx+b
斜率k=-1/(5/4)=-4/5
y=-4x/5+b
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