log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
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log214-2log27/3+log27-log218是多少2是小2log214-2log27/3+log27-log218是多少2是小2log214-2log27/3+log27-log218是多
log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
log2 14-2log2 7/3+log2 7-log2 18是多少
2是小2
log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
运用
loga xy=loga x +loga y
loga x/y=loga x-loga y
系数其实就是幂次,直接提进去作为幂次就可以啦.
把上面的式子合并到一起就可以了.
原式=log2 (14/49*9*7/18)
=log2(1)
=0
LOG(2,√18)+(1/2)LOG(2,56)-LOG(2,3√7)
=(1/2)(LOG(2,2)+LOG(2,3^2))+(1/2)(LOG(2,8)+LOG(2,7))-LOG(2,√63)
=(1/2)+LOG(2,3)+3/2+(1/2)LOG(2,7)-(1/2)(LOG(2,3^2)+LOG(2,7)
=2+LOG(2,3)+(1/2)LOG(2,7)-LOG(2,3)-(1/2)LOG(2,7)
=2
原式=log2(14÷(7/3)² *7/18)
=log2[14*9*7/(49*18)]
=log2(1)
=0
log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
log2^(4^7*2^5)+log2^6-log2^3
求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
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如何把2log2 7转化为 2（log2 14）-log2 2
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以2为底的对数值是多少?像log2(3),log2(5),log2(7).这种
log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 48
(log2 9)/(log2 8) = 2/3(log2 3)
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|[log2(x)]^2-3log2(x)+1|
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log2^6-log2^3
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