若x/2=y/3=z/4,则2x+3y+z/x的值为
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若x/2=y/3=z/4,则2x+3y+z/x的值为若x/2=y/3=z/4,则2x+3y+z/x的值为若x/2=y/3=z/4,则2x+3y+z/x的值为设x/2=y/3=z/4=t∴x=2t,y=
若x/2=y/3=z/4,则2x+3y+z/x的值为
若x/2=y/3=z/4,则2x+3y+z/x的值为
若x/2=y/3=z/4,则2x+3y+z/x的值为
设x/2=y/3=z/4=t
∴x=2t,y=3t,z=4t
把x=2t,y=3t,z=4t代入(2x+3y+z)/x得
原式=(4t+9t+4t)/2t
=17/2
设x/2=y/3=z/4=k,则x=2k,y=3k,z=4k,
则2x+3y+z/x=(4k+9k+4k)/2k=17/2
x:y:z=2:3:4
前面应该是有括号的吧,(2x+3y+z)/x=17/2
希望能帮到你,谢谢
都取倒数依然成立(xyz≠0)
2x=3y=4z
x/2=y/3=z/4
你可以2x=3y
x=2y/3
联立应该可以得出得数来吧
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