若cos(5π/12+θ)=1/7,则sin(π/12-θ)

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若cos(5π/12+θ)=1/7,则sin(π/12-θ)若cos(5π/12+θ)=1/7,则sin(π/12-θ)若cos(5π/12+θ)=1/7,则sin(π/12-θ)sin(π/12-&

若cos(5π/12+θ)=1/7,则sin(π/12-θ)
若cos(5π/12+θ)=1/7,则sin(π/12-θ)

若cos(5π/12+θ)=1/7,则sin(π/12-θ)
sin(π/12-&)=cos(π/2-(5π/12+&))=sin(5π/12+&)=(4·3^1/2)/7