求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 13:06:26
求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]求值(2-4cos^212度)/[csc12度(3-
求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]
求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]
求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]
(2-4cos^212度)/[csc12度(3-根号3tan12度)]
=-2cos24/[csc12度(3-根号3tan12度)]
=-2sin12cos24/(3-根号3tan12度)
=-√3cos12sin12cos24/(√3/2*cos12-1/2*sin12)
=-√3/2*sin24cos24/sin(60-12)
=-√3/4*sin48/sin48
=-√3/4
求值(2-4cos^212度)/[csc12度(3-根号3tan12度)]
sin(x+30)*cos(x+45)求值:sin(x+30度)*cos(x+45度)*csc(45度-x)*tg(60度+x)*tg(30度-x)*sec(60度-x)x没给!
求值Cos pai/17 *cos 2pai/17*cos 4pai/17*cos 8pai/17
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
求值:cos^2 1度+cos^2 2度+…+cos^2 180度=___.
化简求值cos(π/7)cos(2π/7)cos(4π/7)
求值:cos(2pai/7)+cos(4pai/7)+cos(6pai/7)pai打不出,不好意思
求证:cos^8x-sin^8x-cos2x = 1/8(cos6x - cos2x)还有,csc^4a(1-cos^4a)-2cot^2a
sin^2 a/sec^2-1 +cos^2 a/csc^2-1+cos^acsc^a
化简[(secα-cosα)*(cscα-sinα)]/2sinα*cosα
求值(根号3tan12°-3)/[sin12°(4cos^212°-2)]
求值:(根号3tan12°-3)/(4cos^212°-2sin12°)
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
求值: 2(sin^6 θ+cos^6 θ)-3(sin^4 θ+cos^4 θ)
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值
sinx=根号3/2 90〈X〈180度 求 cos x ,tan x ,cot x,sec x,csc x 等于多少