1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)
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1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)(-x+xy+
1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)
1/x-1/y=5
求(-x+xy+y)/(2x+7xy-2y)
1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)
(-x+xy+y)/(2x+7xy-2y)
=(1/x-1/y+1)/(7-2(1/x-1/y))
=(5+1)/(7-10)
=6/(-3)
=-2
由1/x-1/y=5 得
(y-x)/xy=5
y-x=5xy
-x+xy+y=y-x+xy=5xy+xy=6xy
2x+7xy-2y=-2(y-x)+7xy=-10xy+7xy=-3xy
所以(-x+xy+y)/(2x+7xy-2y)=6xy/-3xy=-2
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