关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
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关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
关于存款的数学问题
I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000?
大概译文：
我现在有$11,000,每月0.75％的银行赚取利息.我需要买21000美元作首付的房子.我可以每月多存下100元.需要多长时间我才能有21000美元?
保留两位有效小数
关于存款的数学问题I now have $11,000 in the bank earning interest of .75% per month. I need $21,000 to make a down payment on a house. I can save an additional $100 per month. How long will it take me to accumulate the $21,000? 大概译文
假设经t个月能实现
令q=0.75%,则有：
11000*(1+q)^t+100(1+q)^t+100(1+q)^(t-1)+...+100=21000
利用等比数列求和,可解得：
t=45.53
根据实际意义,应取46个月
复利计算问题
11000×（1+0.75）n次幂+100×（1+0.75）1次幂+100×（1+0.75）2次幂+……+100×（1+0.75）n次幂≥21000即可。
有公式的
http://baike.baidu.com/link?url=GYwFuIiV_tL-sOdeDNTtiG2LWH5KTVCiRhBCx0jVf0bQTZhqwHCAMxGz6yCYaFLl
财务分析里面的等额多次支付问题
月利率=0.75% 年利率=[(1+0.0075)^12]-1=0.938
假如你存n年吧
固定资金11000的收益：11000*[1+0.938]^n
每月存款收益 1000*[(1+0.0075)^12n - 1]/0.0075
两者之和是21000
求取n