log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,
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log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,log4^(1+根号2+根号
log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,
log4^(1+根号2+根号3)+log4^(1+根号2-根号3)
呵呵,摆脱了,呵呵,
log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,
=log4^[两个括号相乘]
真数=[(1+√2)+√3][(1+√2)-√3]
=(1+√2)^2-3
=2√2
所以原式=log4^(2√2)
=lg(2√2)/lg4
=lg2^(3/2)/lg2^2
=(3/2)lg2/2lg2
=3/4
log4(1+根号2+根号3)+log4(1+根号2--根号3)=log4((1+根号2+根号3)(1+根号2-根号3))=log4((1+根号2)的平方-3)=log4(2根号2)
数学题计算log4 8-log1/9 3+log根号2 1/4计算log4 8-log1/9 3+log根号2 1/4计算【3^(log3 根号5)】+【根号3^(log3 1/5)】
计算:2^log4(2--根号3)^2+2^log(2+根号3)^2
(log2 5+log4 125)log3 2/ log根号3 5
log4^(1+根号2+根号3)+log4^(1+根号2-根号3)呵呵,摆脱了,呵呵,
(log2(5)+log4(125))×log3(2)/log根号3(5)
log4 8-log1/9 3=log 根号2 1/4怎么算
log25^2/1*log4^5-log1/3^3-log2^4+5^log根号5^2要过程,答案为11分之4log25^2/1*log4^5-log1/3^3-log2^4+5^log根号5^2过程啊,
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
log4^(根号5-根号3)+log4^(根号5+根号3)=?
log4(根号5-根号3)+log4(根号5+根号3)等於?
log(根号2-1)(3
log 底数是4根号3 真数是81 log4根号3 81 最好有分析!
[log(3)3^1/2]^2+log(0.25)1/4+9log5根号5-log(根号3)1=?
log5[log根号2-1(1/根号(3+2根号2))] 等于多少?如图
log(2)根号18+1/2log(2)56-log(2)3根号7
关于log的计算log8(9)* log27 (32)log4 (3) *log9(2)- log 1/2(四倍根号下32)[log2(5)+log4(0.2)][log5(2)+log25(0.5)]小括号里的数字是真数,小括号外的数字是底数
log(根号3+根号2) (根号3-根号2) 求值.
已知0<a<1,x=log a 根号2+log a 根号3y=1/2 log a 5z=log a 根号21 -log a 根号3比较x y z 的大小关系x=log a (根号2)+log a (根号3)y=1/2 (log a 5)z=log a (根号21) -log a (根号3)