若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=
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若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=若2m-3n=2,2m+3n=-1,则3(2m+3n
若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=
若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=
若2m-3n=2,2m+3n=-1,则3(2m+3n)-2(2m-3n)=
整体带入.
原式=3*(-1)-2*2=-5
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?
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若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
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已知m-3n=2m+n-15=1,则m=?,n=?