x=4*sin(2*pi*0.01*t).*sin(2*pi*3*t)+2*cos(pi*t*t/4);在matlab中怎样表达运行出现错误：Error using ==> mtimesInner matrix dimensions must agree.

x=4*sin(2*pi*0.01*t).*sin(2*pi*3*t)+2*cos(pi*t*t/4);在matlab中怎样表达运行出现错误：Error using ==> mtimesInner matrix dimensions must agree. Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 其中0 matlab rotate程序求大神修改t=0:pi/1000:3.5*pi;k=fix(2*t/pi)+1;x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k.*cos(t);y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k.*sin(t);h=plot(x,y,'r');m=pi:pi/20:4.5*pi;n=fix(2*m/pi)-1;x0=2*cos(1.25*pi);y0=2*sin(1.25*pi);x2= 这是一个关于利用matlab设计凸轮的程序,程序是t=194/120:0.01:256/120;% 回程阶段x=[1170/(31*pi)]*[-1+cos((120*pi*t-194*pi)/31);y=13*[1+194/62-(120*t)/62+1/(2*pi)*sin((240*pi*t)/62-(194*pi)/31)];hold on plot(x,y,'-r');但为什么运 2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ] f(2x)=sin (x+3*pi/4)+cos (x-pi/2), MATLAB中dsolve解出的t是什么含义?我使用了dsolve（’Dy = sin(pi*x*y)‘）；然后结果中：atan(2/(1+exp(2*t*pi*x+2*C1*pi*x))*exp(t*pi*x+C1*pi*x),-(exp(2*t*pi*x+2*C1*pi*x)-1)/(1+exp(2*t*pi*x+2*C1*pi*x)))/x/pi有t和c1两个量,c1想 f(x)h(x)=√2/2sin(x+pi/4)cos(x+5pi/4) =-√2/2sin(x+pi/4)cos(x+pi/4)√2/2sin(x+pi/4)cos(x+5pi/4) =-√2/2sin(x+pi/4)cos(x+pi/4)这个是怎么化出来的? Matlab程序编写和出图u(x,t) = 10 + 5*cos(2*pi*t/T) + (1 + cos(2*pi*t/T))*x/5 + sum{n=1 to n=N} ( (10/pi*n [(T/2*pi) * sin(2*pi*t/T) - (25/(pi*n))^2 cos(2*pi*t/T)] * sin(pi*n*x/25) )I need it once with T=1 and once with T=365.Also for N you can 已知sin(x+pi/6)=1/4,求sin（5pi/6-x)+sin^2(pi/3-x)的值 MATLAB那出错了,画出来的是一条直线,m为一个值,求大神回答t=0:0.01:1;m=-((2*pi*sin((2*pi*t)/9))/9-(5*pi*sin((pi*t)/180))/18)/((2*pi*cos((2*pi*t)/9))/9-(5*pi*cos((pi*t)/180))/18);plot(t,m); matlab中x(t,1)=sin(0.01*pi*t)什么意思 matlab中问题：x = A1 * sin(2 * pi * f1 * t) + A2 * sin(2 * pi * f2 * t) + rand(size(t))f1=364.21 ,f2= 124.7,A1 matlab 中如何根据这个函数 tanx=(2(cost-cos(pi/4)*sin(t)) /(2(cost-cos(pi/4))*cos(t)+1) 画出拟合曲matlab 中如何根据这个函数 tanx=(2(cost-cos(pi/4)*sin(t)) /(2(cost-cos(pi/4))*cos(t)+1) 画出(x和t)拟合曲线 t 取值范围是 如何绘制f（x（1）,x（2））=21.5+x(1)*sin(4*pi*x(1))+x(2)*sin(20*pi*x(2); 这个函数图,用matlabs.t-3-x(1) matlab参数方程绘图问题t=0:pi/1000:3*pi k=fix(2*t/pi)+1; y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k*sin(t); x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k*cos(t); plot(x,y) axis equal 为什么不能运行啊, If sin(x) = 4/5,pi/2 < x < pi,find the value of sin(2x) 为什么sinx-cosx=√2sin(x-Pi/4)?