(12x-24)X1/15+12/15+84/20=12x/14-3 求x是多少 kkkkkkkkk

(12x-24)X1/15+12/15+84/20=12x/14-3 求x是多少 kkkkkkkkk 求几道一元二次方程的过程(11)x^2+15x-54=0 x1=-18 x2=3 (12)x^2+11x+18=0 x1=-2 x2=-9 (13)x^2-9x+20=0 x1=4 x2=5 (14)x^2+19x+90=0 x1=-10 x2=-9 (15)x^2-25x+156=0 x1=13 x2=12 (16)x^2-22x+57=0 x1=3 x2=19 (17)x^2-5x-176=0 x1=16 x2=-11 (18)x^2-26x+ LP模型：max 50x1 +80x2 +30x3 +40x4 +15x5s.t.500x1 +1000x2 +100x3 +300x4 +80x5 ≤20 000x1 + x2 ≥8x3 + x4 ≥15500x1+ 1000x2 ≤12 000x1 ≤16,x2≤10,x3≤24,x4≤4,x5≤25,x1,x2,…,x5 ≥0.max z=50x1 +80x2 +70x3,s.t.12x1 +7x2 +8x3 ≤ 80002x1 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X+X3-X4=1 2X1+3X2+X3+X4=12X1+2X2+2X3-X4=15X1+5X2+2X3=22.3 1 0A= -4 -1 0 的特征值和特征向量.4 -8 2 1.用基础解系表示线性方程组的通解X1 +2X2+3X3-X4=13X1+2X2+X3-X 解一元一次不等式(X-12)x1/0.5 - ( X+1)x1/0.75 > 18 因式分解的问题.已知(x+x1)(x+x2)=x^2+2x-15,且x1≥x2,求x1,x2的值. matlab菜鸟问题>> x=0:.12:1;>> y=(x.^2-3*x+5).*exp(-5*x).*sin(x);>> plot(x,y,'o',x,y)>> x1=0:.12:1;>> y0=(x1.^2-3*x1+5).*exp(-5*x1).*sin(x1);>> y1=interp1(x,y,x1);>> y2=interp1(x,y,x1,'cubic');>> y3=interp1(x,y,x1,'spline');>> y4=interp1(x,y,x1,'n matlab中求解二元函数的极小值,20分.x0=[22,38];x1=[8,13];x2=[5,81];x3=[52,32];x4=[38,11];x5=[16,12];x6=[81,63];x7=[18,45];x8=[62,12];A=[17,40,60,25,30,15,50,8,35];w=A*[sqrt((x-x0)*(x-x0)`);sqrt((x-x1)*(x-x1)`);sqrt((x-x2)*(x-x2)`);sqrt((x-x 5.若x1、x2、x3、x4、x5满足下列方程组：若x1、x2、x3、x4、x5满足下列方程组：2x1+x2+x3+x4+x5=6,x1+2x2+x3+x4+x5=12,x1+x2+2x3+x4+x5=24,x1+x2+x3+2x4+x5=48,x1+x2+x3+x4+2x5=96 则3x4+2x5的值是多少?{凡是X后的均位数的读 若X1,X2,X3,X4,X5 满足方程组：2X1+X2+X3+X4+X5=6,①X1+2X2+X3+X4+X5=12 ②X1+X2+2X3+X4+X5=24 ③X1+X2+X3+2X4+X5=48 ④X1+X2+X3+X4+2X5=96 ⑤⑴求X1+X2+X3+X4+X5的值；⑵求3X3+2X4-X5有必要说明一下,凡是跟在X后面的数字都是小 求x^3-15x^2+16x-80一个实根,下面程序怎么算不出来#include#includefloat f(float x){return ((x-5)*x-16)*x-80;}float xpoint(float x1,float x2){return (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));}float root(float x1,float x2){float x,y,y1;y1=f(x1);do{ (X1除以12)加上(X2除以15)等于7求公式X1跟X2怎么算出来 X1/12+X2/15=7 我已经知道X1=60 X2=30就是想知道用什么公式计算出来, 解方程：x1/6+x=14/15 写出2008x²-2007x-2009=0的两根积与和,x1×x2_____,x1+x2_______.设方程15x²+20x-9=0的两根为x1,x2,则x1²+x2²=_______ 2x1+x2+x3+x4+x5=6 x1+2x2+x3+x4+x5=12 x1+x2+2x3+x4+x5=24 x1+x2+x3+2x4+x5=48 x1+x2+x3+x4+2x5=96x后面的数字是角标多元一次方程组，五个未知数都要求出来， 请教高手如何用matlab解多元二次不等式的解,有三个未知数x1,x2,x3,约束条件如下：0.36x1+0.25x2+0.39x3取最大12/5*x1+11/5*x2+10/3*x3-3/5*x1*x2-x1*x3-1/15*x2*x3-31/75*x1^2-1/25*x2^2 1/2x+4+[x-(1/2x+4)]x1/2+12+16=x 解方程（好的追加分）解方程(0+x^2/4-x-3)^2+(x1-x)^2=17x^2-4x-12=2x1-2x算出X与X1