数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式
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数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式数列an满足a{1}=2,3a{n+1}=2a{
数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式
数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式
数列an满足a{1}=2,3a{n+1}=2a{n}+1.求a{n}通项公式
3a(n+1)=2an+1
3a(n+1)-3=2an-2
[a(n+1)-1]/(an -1)=2/3,为定值.
a1-1=2-1=1,数列{an -1}是以1为首项,2/3为公比的等比数列.
an -1=1×(2/3)^(n-1)=(2/3)^(n-1)
an=1+(2/3)^(n-1)
数列{an}的通项公式为an=1+(2/3)^(n-1)
(2/3)^(n-1)表示2/3的n-1次方.
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