lim n趋向无穷大 (1+1/2+1/4+...+1/2的次方)求极限 谢谢 需要详细过程说明

lim (1+1/2n)^n n趋向于无穷大 lim√1+1/n^2 n趋向于无穷大 lim n趋向无穷大3n^3+n^2-3/4n^3+2n+1 lim(1+1/n+1）^n.趋向无穷大 紧急：求 lim n*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大； n趋向于无穷大,lim n[ln(n+2)-ln(n+1)], 求lim(1+1/n+2)=n->0的极限?（n趋向无穷大） 证明lim(n/(n^2+1))=0(n趋向于无穷大） lim(n^2(cos1/n-1))(n趋向于无穷大） 证明 lim(1-1/2^n)=1 n趋向于无穷大 lim(1-1/2^n)=1 n趋向于无穷大 求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方) lim n趋向无穷大(3^n+2^n)/(3^（n+1）-2^（n+1）)=? lim n趋向无穷大 (2^3n-3^2n-1)/(2^3n+3^2n)=? 用夹逼准则求lim(1/n^2+1/(n^2+1)+...+1/(2n)^2),n趋向于无穷大 lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大 lim(x趋向无穷大)[1+2/(x+2)]^(x+2) lim x趋向无穷大 (1+2/x)^x=?