已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值
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已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值已知x^2+xy=12,xy
已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值
已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值
已知x^2+xy=12,xy+y^2=15,求代数式(x+y)^2-2y(x+y)的值
原式=x²+2xy+y²-2xy-2y²
=x²-y²
=x²+xy-xy-y²
=(x²+xy)-(xy+y²)
=12-15
=-3
x²+xy=12 (1)
xy+y²=15 (2) (1)+(2)得: x²+2xy+y²=27 即:(x+y)²=27
(2)×2得: 2xy+2y²=30
代数式 (x+y)²-2y(x+y)
= (x+y)²-(2xy+2y)
=27 -30
=-3
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