已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y

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已知x-xy=21,xy-y=-12,分别求式子x-y与x-2xy+y已知x-xy=21,xy-y=-12,分别求式子x-y与x-2xy+y已知x-xy=21,xy-y=-12,分别求式子x-y与x-

已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y
已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y

已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y

两式相加x-xy+xy-y=21-12 x-y=9
两式相减x-xy-xy+y=21+12 x-2xy+y=33

x-xy=21 ......................1
xy-y=-12.......................2
1式加2式得:
(x-xy)+(xy-y)=21-12
即:x-y=9
1式减2式得:
(x-xy)-(xy-y)=21-(-12)
即:x-2xy+y=33

好像在哪里做过

9
33

x2-y2=9