4 2X -5X +4

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42X-5X+442X-5X+442X-5X+4大概是:x^4-5x^2+4=(x^2-1)(x^2-4)=(x+1)(x-1)(x+2)(x-2)题目是X^4-5X²+4=0?X^4(X的

4 2X -5X +4
4 2
X -5X +4

4 2X -5X +4
大概是:
x^4-5x^2+4
=(x^2-1)(x^2-4)
=(x+1)(x-1)(x+2)(x-2)

题目是 X^4-5X²+4=0 ? X^4(X的四次方)
解 因式分解
原方程式可变形得
(x²-4)(x²-1)=0
则 x²=4 或 x²=1
即 x=±2 或 x=±1
即 x1=2 x2=-2 x3=1 x4=-1
解答完毕

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