4 2X -5X +4
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42X-5X+442X-5X+442X-5X+4大概是:x^4-5x^2+4=(x^2-1)(x^2-4)=(x+1)(x-1)(x+2)(x-2)题目是X^4-5X²+4=0?X^4(X的
4 2X -5X +4
4 2
X -5X +4
4 2X -5X +4
大概是:
x^4-5x^2+4
=(x^2-1)(x^2-4)
=(x+1)(x-1)(x+2)(x-2)
题目是 X^4-5X²+4=0 ? X^4(X的四次方)
解 因式分解
原方程式可变形得
(x²-4)(x²-1)=0
则 x²=4 或 x²=1
即 x=±2 或 x=±1
即 x1=2 x2=-2 x3=1 x4=-1
解答完毕
(-x^4)^2-2(x^2)^3×x×x+(-3x)^3×x^5
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
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