(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
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(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5/x4)-(x-4/x-3)(x-3/x-2)-(x-2/x-1)=(x-5
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
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(X+1)X(X+2)X(X+3)=504
七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X.
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
x(x-2)-2x(x+1)-3x(x-5) 其中x=负½
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
(x+1)/(x+2)+(x+8)/(x+9)解答x+1/x+2+x+8/x+9=x+2/x+3+x+7/x+8
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,